-(2/3)x^2-19=-35

Solution for -(2/3)x^2-19=-35 equation:

-(2/3)x^2-19=-35

We move all terms to the left:

-(2/3)x^2-19-(-35)=0


Domain of the equation: 3)x^2!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

-(+2/3)x^2-19-(-35)=0

We add all the numbers together, and all the variables

-(+2/3)x^2+16=0

We multiply all the terms by the denominator


-(+2+16*3)x^2=0

We add all the numbers together, and all the variables

-50x^2=0

a = -50; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-50)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{-100}=0$